Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Updated On: 9-6-2021

Apne doubts clear karein ab Whatsapp par bhi. Try it now.

CLICK HERE

Loading DoubtNut Solution for you

Watch 1000+ concepts & tricky questions explained!

1.2 K+

57

Text Solution

`b(x-x_(1))^(2)-2h(x-x_(1))(y-y_(1))+a(y-y_(1))^(2)=0``b(x-x_(1))^(2)+2h(x-x_(1))(y-y_(1))+a(y-y_(1))^(2)=0``a(x-x_(1))^(2)-2h(x-x_(1))(y-y_(1))+b(y-y_(1))^(2)=0` none of these

Answer :

ASolution :

We know that the equation of the lines passing through the origin and perpendicular to the lines given by `ax^(2)+2hxy+by^(2)=0` is `bx^(2)-2hxy+ay^(2)=0` <br> Now, shifting the origin at `(x_(1),y_(1))`, the equations of the required lines are <br> `b(x-x_(1))^(2)-2h(x-x_(1))(y-y_(1))+a(y-y_(1))^(2)=0`**Explain Pair of straight lines with examples.**

**What is the General equation of second degree and condition for represent pair of lines ?**

**What is Point of intersection of pair of straight line ?**

**Pair of straight lines through origin**

**Angle between pair of straight line**

**Some special Cases of angle between Pair Of Straight Lines**

**Bisector of angle between the pair of lines**

**Combined equation of pair of lines joining origin and intersection of a curve and line**

**Find the lines whose combined equation is `6x^2+5xy-4y^2+7x+13y-3=0`**

**Find the value of `Lambda` if `2x^2+7xy+3y^2+8x+14y+lambda=0` represent a pair of straight lines.**